import collections


def glue(*args, **kwargs):
    """
        Glue takes in any number of arguments, named or not, and any depth list
        It will flatten them all and return them joined with kwargs['separator']
        (This is the only kwarg that will be used, anything else will be
            included)
    """

    def _flatten(l):
        """
            from: Cristian at http://stackoverflow.com/a/2158532
        """
        for el in l:
            if isinstance(el, collections.Iterable)\
                    and not isinstance(el, basestring):
                for sub in _flatten(el):
                    yield sub
            else:
                yield el

    separator = ' '  # default
    if 'separator' in kwargs:
        separator = kwargs.pop('separator')

    # I dont care what order you submit them in, they will be alphabetical
    kwargs = collections.OrderedDict(
        sorted(kwargs.items(), key=lambda t: t[0]))

    what_to_glue = list(args)
    # Ignore all your keys, because you're doing this wrong anyway
    what_to_glue.extend([v for k, v in kwargs.iteritems()])

    # flatten crap out of this!
    what_to_glue = _flatten(what_to_glue)

    #set separator

    # safeguard against nonstrings
    return separator.join(str(x) for x in what_to_glue)